If you ride in an elevator moving upward with constant speed, your apparent weight is ?

 

C O N C E P T U A L  C H E C K  P O I N T

E L E V A T O R    R I D E

If you ride in an elevator moving upward with constant speed, is your apparent weight

(a) the same as, (b) greater than, or (c) less than mg?

R E A S O N I N G   A N D     D I S C U S S I O N

If the elevator is moving in a straight line with constant speed, its acceleration is zero.
Now, if the acceleration is zero, the net force must also be zero. Hence, the upward force exerted by the floor of the elevator, W(a), must equal the downward force of gravity, mg.
As a result, your apparent weight is equal to mg.

Note that this conclusion agrees with following Equations , with a=0
Wa  = m(g + a)    : When elevator accelerates upward
Wa  = m(g - a)    : When elevator accelerates downward here 
a(y)=-a 

A N S W E R

(a) Your apparent weight is the same as mg.

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